pax_global_header00006660000000000000000000000064134731736570014532gustar00rootroot0000000000000052 comment=a33ce2b6c09022746dc7c37825b29e50e00077ac legacycrypt-0.3/000077500000000000000000000000001347317365700137225ustar00rootroot00000000000000legacycrypt-0.3/.gitignore000066400000000000000000000001101347317365700157020ustar00rootroot00000000000000/build/ /dist/ /*.egg-info __pycache__ *.pyc *.pyo .tox .cache MANIFEST legacycrypt-0.3/.travis.yml000066400000000000000000000012211347317365700160270ustar00rootroot00000000000000language: python matrix: include: - os: linux dist: xenial python: 3.6 env: TOXENV=py36 - os: linux dist: xenial python: 3.7 env: TOXENV=py37 - os: linux dist: xenial python: nightly env: TOXENV=py38 - os: linux dist: xenial python: pypy3.5 env: TOXENV=pypy3 - os: linux dist: trust python: 3.6 env: TOXENV=py36 - os: linux dist: precise python: 3.6 env: TOXENV=py36 install: - pip install --upgrade tox script: - tox legacycrypt-0.3/LICENSE000066400000000000000000000307331347317365700147350ustar00rootroot00000000000000A. HISTORY OF THE SOFTWARE ========================== Python was created in the early 1990s by Guido van Rossum at Stichting Mathematisch Centrum (CWI, see http://www.cwi.nl) in the Netherlands as a successor of a language called ABC. Guido remains Python's principal author, although it includes many contributions from others. In 1995, Guido continued his work on Python at the Corporation for National Research Initiatives (CNRI, see http://www.cnri.reston.va.us) in Reston, Virginia where he released several versions of the software. In May 2000, Guido and the Python core development team moved to BeOpen.com to form the BeOpen PythonLabs team. In October of the same year, the PythonLabs team moved to Digital Creations, which became Zope Corporation. In 2001, the Python Software Foundation (PSF, see https://www.python.org/psf/) was formed, a non-profit organization created specifically to own Python-related Intellectual Property. Zope Corporation was a sponsoring member of the PSF. All Python releases are Open Source (see http://www.opensource.org for the Open Source Definition). Historically, most, but not all, Python releases have also been GPL-compatible; the table below summarizes the various releases. Release Derived Year Owner GPL- from compatible? (1) 0.9.0 thru 1.2 1991-1995 CWI yes 1.3 thru 1.5.2 1.2 1995-1999 CNRI yes 1.6 1.5.2 2000 CNRI no 2.0 1.6 2000 BeOpen.com no 1.6.1 1.6 2001 CNRI yes (2) 2.1 2.0+1.6.1 2001 PSF no 2.0.1 2.0+1.6.1 2001 PSF yes 2.1.1 2.1+2.0.1 2001 PSF yes 2.1.2 2.1.1 2002 PSF yes 2.1.3 2.1.2 2002 PSF yes 2.2 and above 2.1.1 2001-now PSF yes Footnotes: (1) GPL-compatible doesn't mean that we're distributing Python under the GPL. All Python licenses, unlike the GPL, let you distribute a modified version without making your changes open source. The GPL-compatible licenses make it possible to combine Python with other software that is released under the GPL; the others don't. (2) According to Richard Stallman, 1.6.1 is not GPL-compatible, because its license has a choice of law clause. According to CNRI, however, Stallman's lawyer has told CNRI's lawyer that 1.6.1 is "not incompatible" with the GPL. Thanks to the many outside volunteers who have worked under Guido's direction to make these releases possible. B. TERMS AND CONDITIONS FOR ACCESSING OR OTHERWISE USING PYTHON =============================================================== PYTHON SOFTWARE FOUNDATION LICENSE VERSION 2 -------------------------------------------- 1. This LICENSE AGREEMENT is between the Python Software Foundation ("PSF"), and the Individual or Organization ("Licensee") accessing and otherwise using this software ("Python") in source or binary form and its associated documentation. 2. Subject to the terms and conditions of this License Agreement, PSF hereby grants Licensee a nonexclusive, royalty-free, world-wide license to reproduce, analyze, test, perform and/or display publicly, prepare derivative works, distribute, and otherwise use Python alone or in any derivative version, provided, however, that PSF's License Agreement and PSF's notice of copyright, i.e., "Copyright (c) 2001, 2002, 2003, 2004, 2005, 2006, 2007, 2008, 2009, 2010, 2011, 2012, 2013, 2014, 2015, 2016, 2017, 2018 Python Software Foundation; All Rights Reserved" are retained in Python alone or in any derivative version prepared by Licensee. 3. In the event Licensee prepares a derivative work that is based on or incorporates Python or any part thereof, and wants to make the derivative work available to others as provided herein, then Licensee hereby agrees to include in any such work a brief summary of the changes made to Python. 4. PSF is making Python available to Licensee on an "AS IS" basis. PSF MAKES NO REPRESENTATIONS OR WARRANTIES, EXPRESS OR IMPLIED. BY WAY OF EXAMPLE, BUT NOT LIMITATION, PSF MAKES NO AND DISCLAIMS ANY REPRESENTATION OR WARRANTY OF MERCHANTABILITY OR FITNESS FOR ANY PARTICULAR PURPOSE OR THAT THE USE OF PYTHON WILL NOT INFRINGE ANY THIRD PARTY RIGHTS. 5. PSF SHALL NOT BE LIABLE TO LICENSEE OR ANY OTHER USERS OF PYTHON FOR ANY INCIDENTAL, SPECIAL, OR CONSEQUENTIAL DAMAGES OR LOSS AS A RESULT OF MODIFYING, DISTRIBUTING, OR OTHERWISE USING PYTHON, OR ANY DERIVATIVE THEREOF, EVEN IF ADVISED OF THE POSSIBILITY THEREOF. 6. This License Agreement will automatically terminate upon a material breach of its terms and conditions. 7. Nothing in this License Agreement shall be deemed to create any relationship of agency, partnership, or joint venture between PSF and Licensee. This License Agreement does not grant permission to use PSF trademarks or trade name in a trademark sense to endorse or promote products or services of Licensee, or any third party. 8. By copying, installing or otherwise using Python, Licensee agrees to be bound by the terms and conditions of this License Agreement. BEOPEN.COM LICENSE AGREEMENT FOR PYTHON 2.0 ------------------------------------------- BEOPEN PYTHON OPEN SOURCE LICENSE AGREEMENT VERSION 1 1. This LICENSE AGREEMENT is between BeOpen.com ("BeOpen"), having an office at 160 Saratoga Avenue, Santa Clara, CA 95051, and the Individual or Organization ("Licensee") accessing and otherwise using this software in source or binary form and its associated documentation ("the Software"). 2. Subject to the terms and conditions of this BeOpen Python License Agreement, BeOpen hereby grants Licensee a non-exclusive, royalty-free, world-wide license to reproduce, analyze, test, perform and/or display publicly, prepare derivative works, distribute, and otherwise use the Software alone or in any derivative version, provided, however, that the BeOpen Python License is retained in the Software, alone or in any derivative version prepared by Licensee. 3. BeOpen is making the Software available to Licensee on an "AS IS" basis. BEOPEN MAKES NO REPRESENTATIONS OR WARRANTIES, EXPRESS OR IMPLIED. BY WAY OF EXAMPLE, BUT NOT LIMITATION, BEOPEN MAKES NO AND DISCLAIMS ANY REPRESENTATION OR WARRANTY OF MERCHANTABILITY OR FITNESS FOR ANY PARTICULAR PURPOSE OR THAT THE USE OF THE SOFTWARE WILL NOT INFRINGE ANY THIRD PARTY RIGHTS. 4. BEOPEN SHALL NOT BE LIABLE TO LICENSEE OR ANY OTHER USERS OF THE SOFTWARE FOR ANY INCIDENTAL, SPECIAL, OR CONSEQUENTIAL DAMAGES OR LOSS AS A RESULT OF USING, MODIFYING OR DISTRIBUTING THE SOFTWARE, OR ANY DERIVATIVE THEREOF, EVEN IF ADVISED OF THE POSSIBILITY THEREOF. 5. This License Agreement will automatically terminate upon a material breach of its terms and conditions. 6. This License Agreement shall be governed by and interpreted in all respects by the law of the State of California, excluding conflict of law provisions. Nothing in this License Agreement shall be deemed to create any relationship of agency, partnership, or joint venture between BeOpen and Licensee. This License Agreement does not grant permission to use BeOpen trademarks or trade names in a trademark sense to endorse or promote products or services of Licensee, or any third party. As an exception, the "BeOpen Python" logos available at http://www.pythonlabs.com/logos.html may be used according to the permissions granted on that web page. 7. By copying, installing or otherwise using the software, Licensee agrees to be bound by the terms and conditions of this License Agreement. CNRI LICENSE AGREEMENT FOR PYTHON 1.6.1 --------------------------------------- 1. This LICENSE AGREEMENT is between the Corporation for National Research Initiatives, having an office at 1895 Preston White Drive, Reston, VA 20191 ("CNRI"), and the Individual or Organization ("Licensee") accessing and otherwise using Python 1.6.1 software in source or binary form and its associated documentation. 2. Subject to the terms and conditions of this License Agreement, CNRI hereby grants Licensee a nonexclusive, royalty-free, world-wide license to reproduce, analyze, test, perform and/or display publicly, prepare derivative works, distribute, and otherwise use Python 1.6.1 alone or in any derivative version, provided, however, that CNRI's License Agreement and CNRI's notice of copyright, i.e., "Copyright (c) 1995-2001 Corporation for National Research Initiatives; All Rights Reserved" are retained in Python 1.6.1 alone or in any derivative version prepared by Licensee. Alternately, in lieu of CNRI's License Agreement, Licensee may substitute the following text (omitting the quotes): "Python 1.6.1 is made available subject to the terms and conditions in CNRI's License Agreement. This Agreement together with Python 1.6.1 may be located on the Internet using the following unique, persistent identifier (known as a handle): 1895.22/1013. This Agreement may also be obtained from a proxy server on the Internet using the following URL: http://hdl.handle.net/1895.22/1013". 3. In the event Licensee prepares a derivative work that is based on or incorporates Python 1.6.1 or any part thereof, and wants to make the derivative work available to others as provided herein, then Licensee hereby agrees to include in any such work a brief summary of the changes made to Python 1.6.1. 4. CNRI is making Python 1.6.1 available to Licensee on an "AS IS" basis. CNRI MAKES NO REPRESENTATIONS OR WARRANTIES, EXPRESS OR IMPLIED. BY WAY OF EXAMPLE, BUT NOT LIMITATION, CNRI MAKES NO AND DISCLAIMS ANY REPRESENTATION OR WARRANTY OF MERCHANTABILITY OR FITNESS FOR ANY PARTICULAR PURPOSE OR THAT THE USE OF PYTHON 1.6.1 WILL NOT INFRINGE ANY THIRD PARTY RIGHTS. 5. CNRI SHALL NOT BE LIABLE TO LICENSEE OR ANY OTHER USERS OF PYTHON 1.6.1 FOR ANY INCIDENTAL, SPECIAL, OR CONSEQUENTIAL DAMAGES OR LOSS AS A RESULT OF MODIFYING, DISTRIBUTING, OR OTHERWISE USING PYTHON 1.6.1, OR ANY DERIVATIVE THEREOF, EVEN IF ADVISED OF THE POSSIBILITY THEREOF. 6. This License Agreement will automatically terminate upon a material breach of its terms and conditions. 7. This License Agreement shall be governed by the federal intellectual property law of the United States, including without limitation the federal copyright law, and, to the extent such U.S. federal law does not apply, by the law of the Commonwealth of Virginia, excluding Virginia's conflict of law provisions. Notwithstanding the foregoing, with regard to derivative works based on Python 1.6.1 that incorporate non-separable material that was previously distributed under the GNU General Public License (GPL), the law of the Commonwealth of Virginia shall govern this License Agreement only as to issues arising under or with respect to Paragraphs 4, 5, and 7 of this License Agreement. Nothing in this License Agreement shall be deemed to create any relationship of agency, partnership, or joint venture between CNRI and Licensee. This License Agreement does not grant permission to use CNRI trademarks or trade name in a trademark sense to endorse or promote products or services of Licensee, or any third party. 8. By clicking on the "ACCEPT" button where indicated, or by copying, installing or otherwise using Python 1.6.1, Licensee agrees to be bound by the terms and conditions of this License Agreement. ACCEPT CWI LICENSE AGREEMENT FOR PYTHON 0.9.0 THROUGH 1.2 -------------------------------------------------- Copyright (c) 1991 - 1995, Stichting Mathematisch Centrum Amsterdam, The Netherlands. All rights reserved. Permission to use, copy, modify, and distribute this software and its documentation for any purpose and without fee is hereby granted, provided that the above copyright notice appear in all copies and that both that copyright notice and this permission notice appear in supporting documentation, and that the name of Stichting Mathematisch Centrum or CWI not be used in advertising or publicity pertaining to distribution of the software without specific, written prior permission. STICHTING MATHEMATISCH CENTRUM DISCLAIMS ALL WARRANTIES WITH REGARD TO THIS SOFTWARE, INCLUDING ALL IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS, IN NO EVENT SHALL STICHTING MATHEMATISCH CENTRUM BE LIABLE FOR ANY SPECIAL, INDIRECT OR CONSEQUENTIAL DAMAGES OR ANY DAMAGES WHATSOEVER RESULTING FROM LOSS OF USE, DATA OR PROFITS, WHETHER IN AN ACTION OF CONTRACT, NEGLIGENCE OR OTHER TORTIOUS ACTION, ARISING OUT OF OR IN CONNECTION WITH THE USE OR PERFORMANCE OF THIS SOFTWARE. legacycrypt-0.3/README.md000066400000000000000000000013201347317365700151750ustar00rootroot00000000000000# Legacy crypt — Function to check Unix passwords The legacycrypt module is a standalone version of https://docs.python.org/3/library/crypt.html This module implements an interface to the crypt(3) routine, which is a one-way hash function based upon a modified DES algorithm; see the Unix man page for further details. Possible uses include storing hashed passwords so you can check passwords without storing the actual password, or attempting to crack Unix passwords with a dictionary. Notice that the behavior of this module depends on the actual implementation of the crypt(3) routine in the running system. Therefore, any extensions available on the current implementation will also be available on this module.legacycrypt-0.3/legacycrypt.py000066400000000000000000000170421347317365700166260ustar00rootroot00000000000000"""Wrapper to the POSIX crypt library call and associated functionality.""" import ctypes as _ctypes from ctypes.util import find_library as _find_library import string as _string from random import SystemRandom as _SystemRandom from collections import namedtuple as _namedtuple __version__ = "0.3" __py_version__ = "3.7.3" # # ctypes replacement for _crypt # class _crypt_data_libcrypt(_ctypes.Structure): """struct crypt_data from glibc's crypt.h struct crypt_data { char keysched[16 * 8]; char sb0[32768]; char sb1[32768]; char sb2[32768]; char sb3[32768]; /* end-of-aligment-critical-data */ char crypt_3_buf[14]; char current_salt[2]; long int current_saltbits; int direction, initialized; }; """ __slots__ = () _fields_ = [ ("keysched", _ctypes.c_char * 16 * 8), ("sb0", _ctypes.c_char * 32768), ("sb1", _ctypes.c_char * 32768), ("sb2", _ctypes.c_char * 32768), ("sb3", _ctypes.c_char * 32768), ("crypt_3_buf", _ctypes.c_char * 14), ("current_salt", _ctypes.c_char * 2), ("current_saltbits", _ctypes.c_int64), ("direction", _ctypes.c_int32), ("initialized", _ctypes.c_int32), ] class _crypt_data_libxcrypt(_ctypes.Structure): """struct crypt_data from libxcrypt's crypt.h #define CRYPT_OUTPUT_SIZE 384 #define CRYPT_MAX_PASSPHRASE_SIZE 512 #define CRYPT_DATA_RESERVED_SIZE 767 #define CRYPT_DATA_INTERNAL_SIZE 30720 struct crypt_data { char output[CRYPT_OUTPUT_SIZE]; char setting[CRYPT_OUTPUT_SIZE]; char input[CRYPT_MAX_PASSPHRASE_SIZE]; char reserved[CRYPT_DATA_RESERVED_SIZE]; char initialized; char internal[CRYPT_DATA_INTERNAL_SIZE]; }; """ __slots__ = () CRYPT_OUTPUT_SIZE = 384 CRYPT_MAX_PASSPHRASE_SIZE = 512 CRYPT_DATA_RESERVED_SIZE = 767 CRYPT_DATA_INTERNAL_SIZE = 30720 _fields_ = [ ("output", _ctypes.c_char * CRYPT_OUTPUT_SIZE), ("setting", _ctypes.c_char * CRYPT_OUTPUT_SIZE), ("input", _ctypes.c_char * CRYPT_MAX_PASSPHRASE_SIZE), ("reserved", _ctypes.c_char * CRYPT_DATA_RESERVED_SIZE), ("initialized", _ctypes.c_char), ("internal", _ctypes.c_char * CRYPT_DATA_INTERNAL_SIZE), ] try: # prefer libxcrypt _libname = _find_library('xcrypt') if _libname is not None: _crypt_data = _crypt_data_libxcrypt else: # fallback to libcrypt _libname = _find_library('crypt') if _libname is not None: _crypt_data = _crypt_data_libcrypt if _libname is not None: _libcrypt = _ctypes.CDLL(_libname) else: raise OSError except OSError: raise ImportError("libcrypt / libxcrypt missing") from None _crypt_r_func = _crypt_func = None if hasattr(_libcrypt, "crypt_r"): _crypt_r_func = _libcrypt.crypt_r _crypt_r_func.argtypes = ( _ctypes.c_char_p, _ctypes.c_char_p, _ctypes.POINTER(_crypt_data) ) _crypt_r_func.restype = _ctypes.c_char_p else: _crypt_func = _libcrypt.crypt _crypt_func.argtypes = ( _ctypes.c_char_p, _ctypes.c_char_p, ) _crypt_func.restype = _ctypes.c_char_p def _crypt_crypt(word, salt): """Hash a *word* with the given *salt* and return the hashed password. [clinic input] crypt.crypt word: str salt: str / *word* will usually be a user's password. *salt* (either a random 2 or 16 character string, possibly prefixed with $digit$ to indicate the method) will be used to perturb the encryption algorithm and produce distinct results for a given *word*. returns Py_BuildValue("s", crypt_result) """ if isinstance(word, str): word = word.encode('utf-8') else: raise TypeError( f"crypt() argument 1 must be str, not {word.__class__.__name__}" ) if isinstance(salt, str): salt = salt.encode('utf-8') else: raise TypeError( f"crypt() argument 2 must be str, not {salt.__class__.__name__}" ) if _crypt_r_func is not None: data = _crypt_data() crypt_result = _crypt_r_func(word, salt, data) # poor man's memory wiping _ctypes.memset(_ctypes.byref(data), 0, _ctypes.sizeof(data)) del data else: crypt_result = _crypt_func(word, salt) return crypt_result.decode('utf-8') if crypt_result else None # # original crypt module # _saltchars = _string.ascii_letters + _string.digits + './' _sr = _SystemRandom() class _Method(_namedtuple('_Method', 'name ident salt_chars total_size')): """Class representing a salt method per the Modular Crypt Format or the legacy 2-character crypt method.""" def __repr__(self): return ''.format(self.name) def mksalt(method=None, *, rounds=None): """Generate a salt for the specified method. If not specified, the strongest available method will be used. """ if method is None: method = methods[0] if rounds is not None and not isinstance(rounds, int): raise TypeError(f'{rounds.__class__.__name__} object cannot be ' f'interpreted as an integer') if not method.ident: # traditional s = '' else: # modular s = f'${method.ident}$' if method.ident and method.ident[0] == '2': # Blowfish variants if rounds is None: log_rounds = 12 else: log_rounds = int.bit_length(rounds-1) if rounds != 1 << log_rounds: raise ValueError('rounds must be a power of 2') if not 4 <= log_rounds <= 31: raise ValueError('rounds out of the range 2**4 to 2**31') s += f'{log_rounds:02d}$' elif method.ident in ('5', '6'): # SHA-2 if rounds is not None: if not 1000 <= rounds <= 999999999: raise ValueError('rounds out of the range 1000 to 999_999_999') s += f'rounds={rounds}$' elif rounds is not None: raise ValueError(f"{method} doesn't support the rounds argument") s += ''.join(_sr.choice(_saltchars) for char in range(method.salt_chars)) return s def crypt(word, salt=None): """Return a string representing the one-way hash of a password, with a salt prepended. If ``salt`` is not specified or is ``None``, the strongest available method will be selected and a salt generated. Otherwise, ``salt`` may be one of the ``crypt.METHOD_*`` values, or a string as returned by ``crypt.mksalt()``. """ if salt is None or isinstance(salt, _Method): salt = mksalt(salt) return _crypt_crypt(word, salt) # available salting/crypto methods methods = [] def _add_method(name, *args, rounds=None): method = _Method(name, *args) globals()['METHOD_' + name] = method salt = mksalt(method, rounds=rounds) result = crypt('', salt) if result and len(result) == method.total_size: methods.append(method) return True return False _add_method('SHA512', '6', 16, 106) _add_method('SHA256', '5', 16, 63) # Choose the strongest supported version of Blowfish hashing. # Early versions have flaws. Version 'a' fixes flaws of # the initial implementation, 'b' fixes flaws of 'a'. # 'y' is the same as 'b', for compatibility # with openwall crypt_blowfish. for _v in 'b', 'y', 'a', '': if _add_method('BLOWFISH', '2' + _v, 22, 59 + len(_v), rounds=1<<4): break _add_method('MD5', '1', 8, 34) _add_method('CRYPT', None, 2, 13) del _v, _add_method legacycrypt-0.3/pyproject.toml000066400000000000000000000017201347317365700166360ustar00rootroot00000000000000[build-system] requires = ["flit"] build-backend = "flit.buildapi" [tool.flit.metadata] module = "legacycrypt" author = "Christian Heimes" author-email = "christian@python.org" maintainer = "Christian Heimes" maintainer-email = "christian@python.org" home-page = "https://github.com/tiran/legacycrypt" description-file = "README.md" classifiers = [ "Development Status :: 5 - Production/Stable", "Programming Language :: Python :: 3.6", "Programming Language :: Python :: 3.7", "Programming Language :: Python :: 3.8", "Programming Language :: Python :: 3 :: Only", "Programming Language :: Python :: Implementation :: CPython", "Programming Language :: Python :: Implementation :: PyPy", "Intended Audience :: Developers", "License :: OSI Approved :: Python Software Foundation License", "Operating System :: POSIX", "Topic :: Security :: Cryptography" ] # 3.5 for pypy3. It supports f"" but not 10_000. requires-python = ">=3.5" legacycrypt-0.3/tests.py000066400000000000000000000074001347317365700154370ustar00rootroot00000000000000import sys import unittest import legacycrypt as crypt class CryptTestCase(unittest.TestCase): def test_types(self): self.assertIs(crypt.crypt('', ''), None) with self.assertRaises(TypeError): crypt.crypt(b'', '') with self.assertRaises(TypeError): crypt.crypt('', b'') self.assertIsInstance(crypt.crypt('mypassword'), str) def test_crypt(self): cr = crypt.crypt('mypassword') cr2 = crypt.crypt('mypassword', cr) self.assertEqual(cr2, cr) cr = crypt.crypt('mypassword', 'ab') if cr is not None: cr2 = crypt.crypt('mypassword', cr) self.assertEqual(cr2, cr) def test_salt(self): self.assertEqual(len(crypt._saltchars), 64) for method in crypt.methods: salt = crypt.mksalt(method) self.assertIn(len(salt) - method.salt_chars, {0, 1, 3, 4, 6, 7}) if method.ident: self.assertIn(method.ident, salt[:len(salt)-method.salt_chars]) def test_saltedcrypt(self): for method in crypt.methods: cr = crypt.crypt('assword', method) self.assertEqual(len(cr), method.total_size) cr2 = crypt.crypt('assword', cr) self.assertEqual(cr2, cr) cr = crypt.crypt('assword', crypt.mksalt(method)) self.assertEqual(len(cr), method.total_size) def test_methods(self): self.assertTrue(len(crypt.methods) >= 1) if sys.platform.startswith('openbsd'): self.assertEqual(crypt.methods, [crypt.METHOD_BLOWFISH]) else: self.assertEqual(crypt.methods[-1], crypt.METHOD_CRYPT) @unittest.skipUnless(crypt.METHOD_SHA256 in crypt.methods or crypt.METHOD_SHA512 in crypt.methods, 'requires support of SHA-2') def test_sha2_rounds(self): for method in (crypt.METHOD_SHA256, crypt.METHOD_SHA512): for rounds in 1000, 10000, 100000: salt = crypt.mksalt(method, rounds=rounds) self.assertIn('$rounds=%d$' % rounds, salt) self.assertEqual(len(salt) - method.salt_chars, 11 + len(str(rounds))) cr = crypt.crypt('mypassword', salt) self.assertTrue(cr) cr2 = crypt.crypt('mypassword', cr) self.assertEqual(cr2, cr) @unittest.skipUnless(crypt.METHOD_BLOWFISH in crypt.methods, 'requires support of Blowfish') def test_blowfish_rounds(self): for log_rounds in range(4, 11): salt = crypt.mksalt(crypt.METHOD_BLOWFISH, rounds=1 << log_rounds) self.assertIn('$%02d$' % log_rounds, salt) self.assertIn(len(salt) - crypt.METHOD_BLOWFISH.salt_chars, {6, 7}) cr = crypt.crypt('mypassword', salt) self.assertTrue(cr) cr2 = crypt.crypt('mypassword', cr) self.assertEqual(cr2, cr) def test_invalid_rounds(self): for method in (crypt.METHOD_SHA256, crypt.METHOD_SHA512, crypt.METHOD_BLOWFISH): with self.assertRaises(TypeError): crypt.mksalt(method, rounds='4096') with self.assertRaises(TypeError): crypt.mksalt(method, rounds=4096.0) for rounds in (0, 1, -1, 1<<999): with self.assertRaises(ValueError): crypt.mksalt(method, rounds=rounds) with self.assertRaises(ValueError): crypt.mksalt(crypt.METHOD_BLOWFISH, rounds=1000) for method in (crypt.METHOD_CRYPT, crypt.METHOD_MD5): with self.assertRaisesRegex(ValueError, 'support'): crypt.mksalt(method, rounds=4096) if __name__ == "__main__": unittest.main() legacycrypt-0.3/tox.ini000066400000000000000000000002541347317365700152360ustar00rootroot00000000000000[tox] isolated_build = True envlist = py36,py37,py38,pypy3 skip_missing_interpreters = True [tox:.package] basepython = python3 [testenv] commands = {envpython} tests.py